A Man, 1.5m Tall, Is On The Top Of A Building. He Observes A Car On The Road At An Angle Of 75\Xc2\Xb0 If The Building Is 30m High How Far Is The Car

A man, 1.5m tall, is on the top of a building. He observes a car on the road at an angle of 75° if the building is 30m high how far is the car from the building?

Answer:

The answer to this question is 8.44 m.

Step-by-step explanation:

This problem is best illustrated in the photo below.

First, we must know that the angle stated in the problem is the angle of depression. Angle of depression is the angle between the horizontal and the line of sight of the observer. On the other hand, if the observer is looking upward, then the angle between the horizontal and his line of sight is called the angle of elevation.

Since we have the given angle of depression, we must use its complementary angle to solve for the distance of the car from the building.

Let x = complementary angle of 75°

y = distance of the car from the building

To solve for x,

x+75=90\\x= 90-75\\x = 15

To solve for y, we need to use a trigonometric function that will relate the adjacent of 15° and the opposite of 15°. Let us look at the mnemonics

SOH: Sine =\frac{opposite}{hypotenuse}  

CAH: Cosine = \frac{adjacent}{hypotenuse}

TOA: Tangent = \frac{opposite}{adjacent}

Therefore we must use the tangent function to solve for y.

tan(15) = \frac{opposite}{adjacent}\\ tan(15) = \frac{y}{31.5m}\\ 31.5*tan(15) = y\\y = 8.44 m

If you want to know more about angles of elevation and depression, you may visit the following links:

brainly.ph/question/102161

brainly.ph/question/1249594

brainly.ph/question/903140


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